Since you use Java 8 you can use:
return Arrays.stream(matrix) // Stream<int>
.mapToInt(row -> Arrays.stream(row).sum()) // IntStream
.toArray(); // int
This tip was...
You can write your own predicate:
final Predicate<Map.Entry<?, String>> valueNotNullOrEmpty
= e -> e.getValue() != null && !e.getValue().isEmpty();
Then just use...
I know -1<<31 will give 100000000000000000, so it should give ans (int)Math.pow(2,31) that is equals to 2147483648
That would be the case if int was a two's complement unsigned...
Password transmission and communication encryption are two separate matters.
TLS is initiated over what is at first an unencrypted channel by issuing the STARTTLS command; if the server supports...
There are two reasons for this:
the fact that an Integer implementation, as per the documentation, has an internal cache of at least all values between, precisely, -128 and...
The reason is to be found in the javadoc of the .unlock() documentation of Lock:
A Lock implementation will usually impose restrictions on which thread can...
You are misusing this method. Quoting its documentation (emphasis mine):
index of the search key, if it is contained in the array; otherwise, (-(insertion point) - 1). The...
If Java 7+, use Objects.equals(); its documentation explicitly specifies that:
[...] if both arguments are null, true is returned and if exactly one argument is null, false is returned....
You cannot do that in a portable way. Even with JSR 203.
A Path is two parts:
a root (may be null);
a list of name components.
One problem you have is with the root.
For Unix systems, for...
There is more than one possible argument matcher and one is eq, which is mentioned in the exception message. Use:
verify(function, times(1)).doSomething(eq(arg1), any(Argument2.class));
This is no deficiency.
Lambdas in Java are instances of functional interfaces; which, in turn, are abstracted to instances of Java constructs which can be simplified to one single abstract method,...
The problem is not that the file cannot be found, it is that your code has a compile error.
Another problem is that you seem to want to fill your arrays with numbers, except that it won't...
You can't "remove from a String" since String is immutable. Also, you currently create a new String instance each time you append a character.
Go through a StringBuilder instead :
new String(source.getBytes(inputCharacterCoding), outputCharacterCoding)
This probably does not do what you think it does.
First things first: a String has no encoding. Repeat...
ResultSet user = stat.executeQuery( "SELECT * FROM USER WHERE log_id='" + username + "';" );
This is subject to SQL injection.
Imagine what happens if username has this value:
Maybe you can go through an interface:
public interface FaultCodeProvider
Then have your enums implement it:
public enum DefaultFaultCodes
In this line:
System.out.println(first.get(i) == second.get(i));
no unboxing takes place.
Both sides of the == operator are Object instances; therefore, what will be performed is an object...
User defined attributes, that is any attribute defined by UserDefinedFileAttributeView (provided that your FileSystem supports them!), are readable/writable from Java as byte arrays; if a given...
@mushfek0001 got it right.
The pipe in most regex dialects is a metacharacter for the alternation; basically what you ask the regex engine to do here is: "split against the empty string or... the...
They are very different.
final Path p1 = Paths.get("/usr/src");
final Path p2 = Paths.get("/usr/../usr/src");
p1.equals(p2); // FALSE
Files.isSameFile(p1, p2); // true
Not a class, but you have Integer.SIZE, and so on for Long and floating point classes too. You also have *.BYTES.
Therefore Integer.SIZE is 32, Integer.BYTES is 4, Double.SIZE is 64 and...
public static String filePath = "~//Desktop//";
This will not work. In fact I am surprised that you say that it works on Windows.
You probably meant for the '~' to mean your home...
(still using Java 6 in 2015? Ahwell)
Here is a solution; note that is supposes that you already have a BufferedReader open on the file:
String line, lastLine = null;
while ((line =...
That's one of the numerous problems with File; its .listFiles() method is unreliable.
Try and use this instead:
final Path dir = Paths.get("path/to/directory");
You seem to be misunderstanding something.
For all the system cares, and, MOST OF THE TIME, the developer cares, chars could as well be carrier pigeons, and Strings sequence of said carrier...